Решите уравнение 2х2-9х-10=0
2х²-9х-10=0 а=2 b= -9 c= -10 D = b²-4ac = (-9)²-4*2*(-10) = 81+80 = 161 x₁ = -b-√D / 2a = -(-9)-√161 / 2*2 = 9-√161 / 4 x₂ = -b+√D / 2a = -(-9)+√161 / 2*2 = 9+√161 / 4