{8-5(4-x)=6y-(5-x) {-2(2x+1)+2.5=3(y+2)-8x

Решите задачу:

$\left \{ {{8-5(4-x)=6y-(5-x)} \atop {-2(2x+1)+2,5=3(y+2)-8x}} \right. \\ \\ \left \{ {{x= \frac{3}{2}y + \frac{7}{4} } \atop {-2(2x+1)+2,5=3(y+2)-8x}} \right. \\ -2(2( \frac{3}{2}y+ \frac{7}{4})+1)+2,5=3(y+2)-8( \frac{3}{2}y + \frac{7}{4}) \\ y=-0,5 \\ -2(2x+1)+2,5=3(-0,5+2)-8x \\ x=1 \\ \left \{ {{8-5(4-1)=6(-0,5)-(5-1)} \atop {-2(2*1+1)+2,5=3(-0,5+2)-8*1}} \right. \\ \left \{ {{-7=-7} \atop {-3,5=-3,5}} \right. \\ (x,y)=(1;-0,5)$