Найдите корни уравнения:
(2x² - 5x+2) / 4x = - 5x /( 2x²+7x+2) * * * x≠0 * * *
(2x- 5+2/x) / 4 = - 5 /( 2x+7+2/x ) ; t =2x +2/x
(t -5) /4 = -5/(t+7) ;
(t -5) (t+7) = -20 ;
t² +2t -15 =0 ;
(t-3)(t +5) =0 '
t₁=-5 ; t₂=3 ;
1. 2.
2x +2/x = -5 ; 2x +2/x = 3 ;
2x² +5x +2 = 0 ; 2x² -3x +2 = 0 ; D =3² -4*2*2 = -7 <0<br>x² +(2+1/2)x +2*1/2 = 0 ; x∈ ∅;
x₁=-2 ; x₂=-1/2.