Нужно перевести cout/cin в printf/scanf - C++ #include #include using namespace std;...

Question

Нужно перевести cout/cin в printf/scanf - C++
#include
#include
using namespace std;

int main() {
float a_1, a_2, a_3, x;
cout << "vvod a_1, a_2, a_3" << endl;<br> cin >> a_1 >> a_2 >> a_3;
cout << "Proizved " << a_1*a_2*a_3 << endl;<br> cout << "Sred geometr" << pow (a_1*a_2*a_3, 1./3) << endl; <br>
cout << "vvod x" << endl;<br> cin >> x;
cout << "Po form:" << exp(1/(3*x))-abs(3*x*x-pow(pow(x+1,4) +log((pow(x,4)+4)/(pow(x,2)+2)), 1./5)) << endl;<br>
int a;
cout << "vvod a" << endl;<br> cin >> a;
int c=a%10*10+a/10;
cout << c << endl;<br> system ("pause");
}

Answer 1

#include
#include
#include

int main() {
float a_1, a_2, a_3, x;
printf ("vvod a_1, a_2, a_3\n");
scanf ("%f %f %f",&a_1,&a_2,&a_3);
printf ("Proizved = %f\n",a_1*a_2*a_3);
printf ("Sred geometr = %f\n",pow(a_1*a_2*a_3, 1.0/3));

printf ("vvod x\n");
scanf ("%f",&x);
printf ("Po form: %f\n",exp(1.0/(3*x))-abs(3*x*x-pow(pow(x+1,4)+log((pow(x,4)+4)/(pow(x,2)+2)),1.0/5)));

int a;
printf ("vvod a\n");
scanf ("%d",&a);
int c=a%10*10+a/10;
printf ("%d",c);
system ("pause");
}

Пример:
vvod a_1, a_2, a_3
2 3 5
Proizved = 30.000000
Sred geometr = 3.107233
vvod x
4
Po form: -42.913096
vvod a
71
17