Решим по действиями:
1) 2/(3 - x) - 4x/(9 - x²) = 2/(3 - x) - 4x/(3 - x)(3 + x) = 2(3 + x) - 4x/(3 - x)(3 + x) = (6 + 2x - 4x)/(3 - x)(3 + x) = (6 - 2x)/(3 - x)(3 + x) = 2(3 - x)/(3 - x)(3 + x) =
= 2/(3 + x)
2) 2/(3 + x) - 1/(3 + x) = 1/(3 + x)
3) 1/(3 + x)·(9 + 6x + x²) = (x + 3)²/(x + 3) = x + 3
Ответ: x + 3.