Помогите решить! 100 баллов!!!!

$\frac{x-1}{2}+\frac{x^2+x-4}{4}\ \textgreater \ \frac{0,\:5x^2+1}{3} \\ \\ \frac{x-1}{2}+\frac{x^2+x-4}{4}\ \textgreater \frac{ \frac{1}{2} +x^2}{3} \\ \\ \frac{x-1}{2}+\frac{x^2+x-4}{4}\ \textgreater \frac{ \frac{x^2+2}{2} }{3} \\ \\ \frac{x-1}{2}+\frac{x^2+x-4}{4}\ \textgreater \frac{x^2+2}{6} \\ \\ \frac{x-1}{2}+\frac{x^2+x-4}{4}- \frac{x^2+2}{6} \ \textgreater 0 \\ \\ 6(x-1)+3(x^2+x-4)-2(x^2+2)\ \textgreater \ 0 \\ \\ 6x-6+3x^2+3x-12-2x^2-4\ \textgreater \ 0 \\ \\ 9x-22+x^2\ \textgreater \ 0 \\ \\ x^2+9x-22\ \textgreater \ 0 \\ \\ x^2+11x-2x-22\ \textgreater \ 0$

$x*(x+11)-2(x+11)\ \textgreater \ 0 \\ \\ (x-2)*(x+11)\ \textgreater \ 0 \\ \\ (x-2)(x+11)=0 \\ x1=-11;x2=2 \\ \\$

x∈( ⁻∞,-11) U ( 2 , + ∞)