4x-y-5Z=1x+y-2Z=63x-2y-6Z=2Решить методом Крамера

4-1-5=1
1+1-2=6
3-2-6=2
▲ = $\left[\begin{array}{ccc}4&1&5\\1&1&2\\3&2&6\end{array}\right]$ = 24+10 - 6 - 15 - 16 - 6= 3

▲1 = $\left[\begin{array}{ccc}1&1&5\\6&1&2\\2&2&6\end{array}\right]$ = 6 + 60 + 4 -10 - 4 - 36 = 20

▲2 = $\left[\begin{array}{ccc}4&1&5\\1&6&2\\3&2&6\end{array}\right]$ = 144 + 10 + 6 - 90 - 16 - 6 = 48

▲3 = $\left[\begin{array}{ccc}4&1&1\\1&1&6\\3&2&2\end{array}\right]$ = 8 + 2 + 18 - 3 - 48 - 2 = -25

x1= $\frac{▲1}{▲}$ = $\frac{20}{3}$ = 6.6

x2= $\frac{▲2}{▲}$ = $\frac{48}{3}$ = 16

x3= $\frac{▲3}{▲}$ = $\frac{-25}{3}$ = 8.3

Ответ:(6.6;16;8.3).