ОДЗ: x ≠ -6; x ≠ 6; x ≠ 0
(2x-3)/((x-6)(x+6)) - (x-2)/(x(x-6)) + (x-1)/(x(x+6)) = 0
x(2x-2) - (x+6)(x-2) + (x-6)(x-1) = 0
2x²-2x-(x²-2x+6x-12)+x²-x-6x+6 = 0
2x²-2x-x²+2x-6x+12+x²-x-6x+6 = 0
2x²-13x+18 = 0
D = (-13)²-4*2*18 = 169-144 = 25 = 5²
x₁ = (13+5)/(2*2) = 4.5 ∈ ОДЗ
x₂ = (13-5)/(2*2) = 2 ∈ ОДЗ
Ответ: 4.5; 2