Решите,если можете пожалуйста (на фото)

1) $6: \frac{3}{5} =6 * \frac{5}{3} = 10$
2) $1 \frac{1}{6} * \frac{6}{7}= \frac{7}{6} * \frac{6}{7}= 1$
3) $10-1=9$
4) $4 \frac{1}{5}* \frac{10}{11}= \frac{21}{5} * \frac{10}{11} = \frac{42}{11}$ $=3 \frac{9}{11}$
5) $3 \frac{9}{11} +5 \frac{2}{11}=8 \frac{11}{11} = 9$
6) $\frac{3}{20}+ \frac{1}{2} - \frac{1}{15}= \frac{9+30-4}{60}= \frac{35}{60}= \frac{7}{12}$
7) $\frac{7}{12}* \frac{12}{49}= \frac{1}{7}$
8) $\frac{1}{5}+ \frac{1}{7}= \frac{7+5}{35}= \frac{12}{35}$
9) $\frac{1}{7} : \frac{12}{35}= \frac{1}{7}* \frac{35}{12} = \frac{5}{12}$
10) $1 - \frac{5}{12}= \frac{12}{12}- \frac{5}{12}= \frac{7}{12}$
11) $\frac{7}{12} *2 \frac{1}{3} = \frac{7}{12}* \frac{7}{3} = \frac{49}{36}= 1 \frac{13}{36}$
12) $3 \frac{1}{4} -1 \frac{13}{36}= 3 + \frac{1}{4}-1- \frac{13}{36}=(3-1)+( \frac{1}{4}- \frac{13}{36})=2+ \frac{9-13}{36}= 2- \frac{4}{36} =$ $2- \frac{1}{9}=1 \frac{8}{9}$

Решите,если можете пожалуйста (** фото)