√(x+3-4√(x-1))+√(x+8-6√(x-1))=1 ОДЗ: x-1≥0 x≥1
√((x-1+4-2*2*√(x-1))+√(x-1)+9-2*3*√(x-1))=1
√(√(x-1)²-2*√(x-1)*2+2²)+√(√(x-1)²-2*√(x-1)*3+3²)=1
√(√(x-1)-2))²+√(√(x-1)-3))²=1
√(x-1)-2+√(x-1)-3=1
2√(x-1)-5=1
2√(x-1)=6 |÷2
√(x-1)=3
(√(x-1))²=3²
x-1=9
x=10.
Ответ: х=10.