(7х - 1) (2+х)= (х-4) (х+4) х(8-3х)= (5х-1) в кв

Question

(7х - 1) (2+х)= (х-4) (х+4)

х(8-3х)= (5х-1) в кв

Answer 1

(7х-1)(2+х)=(х-4)(х+4)
14х+7х^2-2-х=х^2-16
13х+7х^2-2-х^2+16=0
5х^2+13х+14=0

х(8-3х)=(5х-1)^2
8х-24х^2=25х^2-10х+1
8х-24х^2-25х^2+10х-1=0
-49х^2+2х-1=0
49х^2-2х+1=0