X(x во 2степени +2+1)=2(x+1)

Решите задачу:

$x \times ( {x}^{2} + 2 + 1) = 2(x + 1) \\ x \times ( {x}^{2} + 3) = 2x + 2 \\ {x}^{3} + 3x = 2x + 2 \\ {x}^{3} + 3x - 2x - 2 = 0 \\ {x}^{3} + x - 2 = 0 \\ {x}^{3} - x + 2x - 2 = 0 \\ x \times ( {x}^{2} - 1) + 2(x - 1) = 0 \\ x \times (x - 1) \times (x + 1) + 2(x - 1) = 0 \\ (x - 1) \times (x \times (x + 1) + 2) = 0 \\ (x - 1) \times ( {x}^{2} + x + 2 ) = 0 \\ x - 1 = 0 \\ {x}^{2} + x + 2 = 0 \\ x = 1$