Пусть а¹/⁴=t ⇒
(v/(v³-v)-v³/(v⁴-v²))*(v+1)=(v/(v*(v²-1)-v³/(v²*(v²-1))*(v+1)=(1/(v²-1)-v/(v²-1))*(v+1)=
=((1-v)/(v²-1))*(v+1)=-(v-1)*(v+1)/((v-1)*(v+1)=-1.
((9a⁻⁵/²⁴)/(a¹/⁸*a⁵/³))¹/³=((9a⁻⁵/²⁴)/(a¹/⁸⁺⁵/³))¹/³=((9a⁻⁵/²⁴)/(a⁴³/²⁴))¹/³=
=(9a⁻⁴⁸/²⁴)¹/³=(9a⁻²)¹/³=(3²/a²)¹/³=(3/a)²/³.