Решите уравнение f'(x) = 0: f (x) = 3x^3 - 2x^2 - 1
F ' (x) = 3*3x^2 - 2*2x = 9x^2 - 4x 9x^2 - 4x = 0 x (9x - 4) = 0 x = 0 ; x = 4/9