1)(х-1)(х+2)=0 2)(2х+3)(х-4)=0

Question

1)(х-1)(х+2)=0
2)(2х+3)(х-4)=0

Answer 1

(x-1)(x+2)=0
x²+2x-x-2=0
x²+x-2=0
D=1-4*(-2)=9
x₁=(-1+3)/2=1
x₂=(-1-3)/2=-2

(2x+3)(x-4)=0
2x²-8x+3x-12=0
2x²-5x-12=0
D=25-4*2*(-12)=121
x₁=(5+11)/4=4
x₂=(5-11)/4=-6/4=-3/2=-1.5