9/10×(1 5/9-4/9÷(5/8+3/8÷3)) решите пожалуйста!!

Решите задачу:

$1) \frac{3}{8} \div 3 = \frac{3}{8} \times \frac{1}{3} = \frac{3 \times 1}{8 \times 3} = \frac{3}{24} = \frac{1}{8}$
$2) \frac{5}{8} + \frac{1}{8} = \frac{5 + 1}{8} = \frac{6}{8} = \frac{3}{4}$
$3) - \frac{4}{9} \div \frac{3}{4} = - \frac{4}{9} \times \frac{4}{3} = - \frac{4 \times 4}{9 \times 3} = - \frac{16}{27}$
$4)1 \frac{5}{9} - \frac{16}{27} = \frac{1 \times 9 + 5}{9} - \frac{16}{27} = \frac{14}{9} - \frac{16}{27} = \frac{3 \times 14}{3 \times 9} - \frac{1 \times 16}{1 \times 27} = \frac{42}{27} - \frac{16}{27} = \frac{42 - 16}{27} = \frac{26}{27}$
$5) \frac{9}{10} \times \frac{26}{27} = \frac{9 \times 26}{10 \times 27} = \frac{234}{270} = \frac{13 \times 18}{15 \times 18} = \frac{13}{15}$