1)
Var A [6..7] = 2 элемента.
Var C [5..13] = 8 элементов.
Var K [0..19] = 20 элементов.
Var A [1..8] = 8 элементов.
Var D [-8..15] = 24 элемента.
2)
1. for h := 1 to 112 do
writeln(h);
2. for i := 0 to 96 do
writeln(i);
3)
1. K[6] = 11
2. R[4] + K[1] = 28
3. 2 + K[6] = 13
4. K[1 + 2] = 7
5. K[5] + 10 = 22
6. 10 * K[4] = 260