Помогите решить 25 баллов

Решите задачу:

$f(x)= \sqrt{ \frac{25-x^2}{x+7}} \\\\OOF:\; \; \left \{ {{\frac{25-x^2}{x+7} \geq 0 } \atop {x+7\ne 0}} \right. \; \; \left \{ {{ \frac{(5-x)(5+x)}{x+7} \geq 0} \atop {x\ne -7}} \right. \; \; \left \{ {{\frac{(x-5)(x+5)}{x+7} \leq 0} \atop {x\ne -7}} \right. \\\\---(-7)+++[-5\, ]---[\, 5\, ]+++\\\\x\in (-\infty ,-7)\cup [-5,5\, ]$