Номер 452, решите пожалуйста с объяснением (1,2)

$\left \{ {{x-y=3} \atop {xy=28}} \right.\\\\ \left \{ {{x=3+y} \atop {(3+y)*y=28}} \right.\\\\ \left \{ {{x=3+y} \atop { y^{2} +3y-28=0}} \right. \\\\ \left \{ {{y=-7} \atop {x=3-7}} \right.\\\\ \left \{ {{x=-4} \atop {y=-7}} \right.\\\\ \left \{ {{y=4} \atop {x=3+4}} \right. \\\\ \left \{ {{x=7} \atop {y=4}} \right.$
Ответ: ( - 4 , - 7), ( 7 ; 4)
$\left \{ {{ y^{2} -x=14} \atop {x-y= - 2}} \right.\\\\ \left \{ {{x=y-2} \atop { y^{2}-y+2-14=0 }} \right.\\\\ \left \{ {{x=y-2} \atop { y^{2}-y-12=0 }} \right.\\\\ \left \{ {{y=4} \atop {x=4-2}} \right.\\\\ \left \{ {{y=4} \atop {x=2}} \right.\\\\ \left \{ {{y=-3} \atop {x=-3-2}} \right.\\\\ \left \{ {{y=-3} \atop {x=-5}} \right.$
Ответ : (2 ; 4) , (- 5 ; - 3)