2*(2/3)ˣ⁻¹ - 4*(3/2)ˣ +1 = 0
2*(2/3)ˣ *(2/3)⁻¹ - 4*(3/2)ˣ +1 = 0
3*(2/3)ˣ -4*(3/2)ˣ +1 = 0
(2/3)ˣ = t
3t -4/t +1 = 0 | * t
3t² - 4 +t = 0
3t² +t - 4 = 0
D = 49
t₁ = (-1+7)/6 = 1
t₂ = (-1 -7)/6 = -8/6 = -4/3
а) (2/3)ˣ = 1
х = 0
б)(2/3)ˣ = -4/3
∅
Ответ: х = 0