ОДЗ
{x+3≥0⇒x≥-3
{7-x≥0⇒x≤7
{10-x≥0⇒x≤10
-3≤x≤7
возводим в квадрат
x+3<7-x+10-x+2√(70-17x+x²)<br>2√(70-17x+x²)>3x-14
4(70-17x+x²)>9x²-84x+196
9x²-84x+196-4x²+68x-280<0<br>5x²-16x-84<0<br>D=256+1680=1936
x1=(16-44)/10=-2,8
x2=(16+44)/10=6
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+ _ +
----[-3]----(-2,8)----------------(6)-----[7]-----
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x∈(-2,8;6)