1)x^4y^2-1=? 2)25a^2b^2-16x^4=? 3)100x^2-y^8=? Памагите плз

Question

1)x^4y^2-1=?
2)25a^2b^2-16x^4=?
3)100x^2-y^8=?
Памагите плз

Answer 1

1). x^4y^2-1=(x^2y-1)*(x^2y+1); 2). 25a^2b^2-16x^4=(5ab-4x^2)*(5ab+4x^2); 3). 100x^2-y^8=(10x-y^4)*(10x+y^4).