(х+3)2-(х+3)-30=0 помогитее
-------------------------- x+3=t t²-t-30=0 t1+t2=1; t1*t2=-30 t1=6; t2=-5 x+3=6; x+3=-5 x=3; x=-8
(х+3)^2-(x+3)-30=0 t=x+3 t^2-t-30=0 d=1+4*30=121 vd=11 t1=1-11/2=-5 t2=1+11/2=6 x+3=5 x1 =2 x2=6-3=3