Буду рад, если поможете

Question

Буду рад, если поможете

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Answer 1

8) S = ∫₃⁵(6x-x²)dx = (3x²-(x³/3))|₃⁵ = (3*25-(125/3)) - (27-(27/3)) =
= 75-27 + (27-125)/3 = 48-32²/₃ = 16 - ²/₃ = 15¹/₃
 
9) S = ∫₁²(2/(x+1))dx =2*∫₁²(1/(x+1))d(x+1) = 2*(ln|x+1|)|₁² = 2*(ln(3) - ln(2)) =
= 2*ln(3/2) ≈ 2*0.405 ≈ 0.8109

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