НУЖНА ПОМОЩЬ СРОЧНО!!!!!!!!!!!!!!!!!!!!

Question

НУЖНА ПОМОЩЬ
СРОЧНО!!!!!!!!!!!!!!!!!!!!

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Answer 1

F`(x)=2cosx/4*(-sinx/4)-2sinx/4*cosx/4=-4sinx/4*cosx/4=-2sinx/2
-2sinx/2=0
sinx/2=0
x/2=πn
x=2πn,n∈z

Answer 2

f`(x)=2cosx/4*(-sinx/4)-2sinx/4*cosx/4=-4sinx/4*cosx/4=-2sinx/2

f'=2cos x/4 * (-sin x/4) - 2sin x/4 * cos x/4= -2sinx/4cosx/4-2sinx/4cosx/4 = 
=-4sinx/4cosx/4 = -2sinx/2

f'=0
-2sinx/2=0
sin x/2 =0
x/2=πn
x=2πn , n∈Z