0 \\ d = 1 - 4 \times 3 \times ( - 1) = \\ = 1 + 12 = 13 \\ x_{1} = \frac{1 - \sqrt{13} }{6} \\ x_{2} = \frac{1 + \sqrt{13} }{6} " alt="3 {x}^{2} - x - 1 > 0 \\ d = 1 - 4 \times 3 \times ( - 1) = \\ = 1 + 12 = 13 \\ x_{1} = \frac{1 - \sqrt{13} }{6} \\ x_{2} = \frac{1 + \sqrt{13} }{6} " align="absmiddle" class="latex-formula">
а>0, ветви параболы направлены вверх.
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