0 \\ x1 = \frac{4 + 10}{6} = \frac{14}{6} = \frac{7}{3} \\ x2 = \frac{4 - 10}{6} = \frac{ - 6}{6} = - 1 " alt="3 {x}^{2} - 4x - 7 = 0\\ d = 16 + 4 \times 3 \times 7 = 16 + 84 = 100 > 0 \\ x1 = \frac{4 + 10}{6} = \frac{14}{6} = \frac{7}{3} \\ x2 = \frac{4 - 10}{6} = \frac{ - 6}{6} = - 1 " align="absmiddle" class="latex-formula">