Lg(2x^2-4x+12)=lgx+lg(x+3)

Question

Lg(2x^2-4x+12)=lgx+lg(x+3)

Answer 1

Lg (2x² - 4x + 12) = lg(x*(x+3))
2x² - 4x +12 = x² +3x
x²- 7x +12 =0
D = 49-48 = 1
x₁ = (7+1) /2 =4
x₂ = (7-1) /2=3
Ответ: 4; 3