|sin(2x+π/10)-1/2)|=1
Sin(2x-π/2)=-1/2 sin(-(π/2-2x)=-1/2 -sin(π/2-2x)=-1/2 sin(π/2-2x)=1/2 cos2x=1/2 2x=π/3+2πn х=π/6+πn х∈(0;3π/2) ⇒ х₁=π/6 x₂=7π/6.