Даю 33б Решите уравнение. x^2+3x+9/x^3+27 - 1/x+3 = 2/x^3-3x+9
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(x²+3x+9)/(x+3)(x²-3x+9)-1/(x+3)=2/(x²-3x+9) x³++27≠0⇒x³≠-27⇒x≠-3 (x²+3x+9)-(x²-3x+9)-2(x+3)=0 x²+3x+9-x²+3x-9-2x-6=0 4x=6 x=1,5