Помогите решить уравнение номер 2.128 Пожалуйста помогите Заранее спасибо!

Надеюсь все понятно
$({x}^{2} - 4x + 4) - 9 = 0 \\ ({x - 2})^{2} - {3}^{2} = 0 \\ (x - 2 - 3)(x - 2 + 3) = 0 \\ (x - 5)(x + 1) = 0 \\ x - 5 = 0 \\ x = 5 \\ x + 1 = 0 \\ x = - 1$
${x}^{2} + 7x + 12 = 0 \\ ( {x}^{2} + 8x + 16) - (x + 4) = 0 \\ ( {x + 4)}^{2} - (x + 4) = 0 \\ (x + 4)(x + 4 - 1) = 0 \\ x + 4 = 0 \\ x = - 4 \\ x + 3 = 0 \\ x = - 3$
${x}^{2} - 11x + 10 = 0 \\ ({x}^{2} - 8x + 16) - ( 3x + 6) = 0 \\ ( {x - 4)}^{2} - 3(x - 4) = 0 \\ (x - 4)(x - 4 - 3) = 0 \\ x - 4 = 0 \\ x = 4 \\ x - 7 = 0 \\ x = 7$
$2 {x}^{2} - 3x + 1 = 0 \\ ( {x}^{2} - 2x + 1) + {x}^{2} - x = 0 \\ ( {1 - x)}^{2} - x(1 - x) = 0 \\ (1 - x)(1 - x - x) = 0 \\ 1 - x = 0 \\ x = 1 \\ 1 - 2x = 0 \\ x = \frac{1}{2}$