Помогитеееееееееее пжлст
(sin(x) + cos(x))² = 1 + cos(x) sin²x + 2sinxcosx + cos²x - 1 - cosx = 0 (sin²x + cos²x = 1) 1 + 2sinxcosx - 1 - cosx = 0 2sinxcosx - cosx = 0 cosx(2sinx - 1) = 0 cosx = 0; x = π/2 2sin x = 1 sinx = 1/2 x = π/6 Ответ: 30°