1) 4
2) 4
3) 1
4) 1
5) 4
6) 4
7) 1
8) 1
9) 4
10) 3
11) 1 - Д, 2- В,3 - А,4 - Г
12)
дано
m(ppa CH3COOH) = 180 g
W(CH3COOH) = 5%
----------------------------
V(CO2)-?
m(CH3COOH) = 180 *5% / 100% = 9 g
CH3COOH+NaHCO3-->CH3COONa+H2O+CO2
M(CH3COOH) = 60 g/mol
n(CH3COOH) = m/M = 9/ 60 = 0.15 mol
n(CH3COOH) = n(CO2) = 0.15 mol
V(CO2) = n*Vm = 0.15 * 22.4 = 3.36 л
ответ 3.36 л