Решить уравнение x^2=2x+8
x^2 = 2x + 8x^2 - 2x - 8 = 0D = (-2)^2 - 4*1*(-8) = 4 + 32 = 36 = 6^2x1 = 2 + 6 / 2*1 = 8/2 = 4x2 = 2 - 6 / 2 = -4/2 = -2
X^2 = 2x + 8 x^2 - 2x - 8 = 0 D = (-2)^2 - 4*1*(-8) = 4 + 32 = 36 = 6^2 x1 = 2 + 6 / 2*1 = 8/2 = 4 x2 = 2 - 6 / 2 = -4/2 = -2
Х²≡2х+8 ײ-2х-8=0 Д=-2²-4×1×(-8)=4+32=36=6² Х1=(2+6)/2= 4 Х2=(2-6)/2= -2