0} \atop { x^{2} -4x +3 <8}} \right. " alt=" \left \{ {{ x^{2} - 4x + 3 >0} \atop { x^{2} -4x +3 <8}} \right. " align="absmiddle" class="latex-formula">
x² - 4x +3 >0
н.ф.: 1; 3
x∈ (-беск.; 1) U(3; +беск.)
x² - 4x + 3<8<br>x² - 4x - 5<0<br>н.ф.: -1; 5
x∈ (-1;5)
Ответ: (-1;1) U (3;5)