Помогите пожалуйста 38.2

Решите задачу:

$\frac{18bc}{24c} = \frac{(6*3)bc}{(6*4)c} = \frac{3b*6c}{4*6c} = \frac{3b}{4} = \frac{3}{4}*b =0.75b \\ \\ \frac{25a^2y}{15by} = \frac{5a^2 * 5y}{3b * 5y} = \frac{5a^2}{3b} \\ \\ \frac{24a^3}{6ac} = \frac{4a^2*6a}{c*6a} = \frac{4a^2}{c} \\ \\ \frac{27x^2y }{21xy^3} = \frac{9x *3xy}{7y^2*3xy} = \frac{9x}{7y^2} \\ \\$

$\frac{-2a^6b^3}{a^3b^5} = \frac{-2a^3 * a^3b^3}{b^2*a^3b^3} = \frac{-2a^3}{b^2} =- \frac{2a^3}{b^2} \\ \\ \frac{x^7y^4}{x^5*y^8} = \frac{x^2 * x^5y^4}{y^4 * x^5y^4} = \frac{x^2}{y^4} \\ \\ \frac{42m^3n^5}{35mn^5} = \frac{6m^2 * 7mn^5}{5*7mn^5} = \frac{6m^2}{5} = \frac{6}{5} *m^2 = 1.2m^2 \\ \\ \frac{75p^4q}{150p^5q} = \frac{1 * 75p^4q}{2p * 75p^4q} = \frac{1}{2p} \\ \\$