ПОЖАЛУЙСТА ПОМОГИТЕ!!!!!!!!ЭТО СРОЧНО!!!!!!!

1)
$\frac{x + 9}{7} = \frac{3 + x + 1}{3} \\ \frac{x + 9}{7} = \frac{x + 4}{3} \\ 3(x + 9) = 7(x + 4) \\ 3x + 27 = 7x + 28 \\ 4x = - 1 \\ x = - \frac{1}{4}$
2)
$1 - \frac{5x - 2}{6} = \frac{x - 5}{9} \\ \frac{6 - 5x + 2}{6} = \frac{x - 5}{9} \\ \frac{8 - 5x}{6} = \frac{x - 5}{9} \\ 9(8 - 5x) = 6( x - 5) \\ 72 - 45x = 6x - 30 \\ 51x = 102 \\ x = 2$
3)
$\frac{3x + 4}{5} + \frac{x - 7}{2} = \frac{2(2x + 3)}{5}$
$2(3x + 4) + 5(x - 7) = 4(2x + 3) \\ 6x + 8 + 5x - 35 = 8x + 12 \\ 11x - 27 = 8x + 12 \\ 3x = 40 \\ x = \frac{40}{3}$

4)
$\frac{7x - 3}{2} - \frac{9 - 4x}{3} = \frac{7 - x}{2} \\ 3(7x - 3) - 2(9 - 4x) = 3(7 - x) \\ 21x - 9 - 18 + 8x = 21 - 3x \\ 29x - 27 = 21 - 3x \\ 32x = 48 \\ x = \frac{48}{32} = \frac{3}{2}$