Знайти суму ряду !!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!
S=lim(n=1,∞) a(n+1) / a(n) S=lim(n=1,∞) (3n+9(n+1)²+1) / (9n²+3n-2)= (делим на n²) =lim(n=1,∞)(3/n+9+18/n+1/n²+1/n²) / (9+3/n-2/n²)= =lim(n=1,∞) (9/9)=1 ответ 1