Нр.14.
0 \\ d = 1 + 4 \times 12 = 49 \\ n1 = \frac{1 + 7}{2} = \frac{8}{2} = 4 \\ n2 = \frac{1 - 7}{2} = - \frac{6}{2} = - 3 \\ n \geqslant 4" alt="nx = {n}^{2} - 12 \\ x = \frac{ {n}^{2} - 12 }{n} \\ \frac{ {n}^{2} - 12}{n} \geqslant 1 \\ {n}^{2} - 12 \geqslant n \\ {n}^{2} - n - 12 > 0 \\ d = 1 + 4 \times 12 = 49 \\ n1 = \frac{1 + 7}{2} = \frac{8}{2} = 4 \\ n2 = \frac{1 - 7}{2} = - \frac{6}{2} = - 3 \\ n \geqslant 4" align="absmiddle" class="latex-formula">
Получим:
n=4
n=6
n=12
Otvet: c) 22