ПОМОГИТЕ СРОЧНО математика
f'(x)=((x+2)/(x^2+1))'=((x+2)'(x^2+1)-(x+2)(x^2+1)')/(x^2+1)^2=(x^2+1-2x(x+2))/(x^2+1)^2=(x^2+1-2x^2-2x))/(x^2+1)^2=(-x^2+1-2x))/(x^2+1)^2;f'(0)=(-0^2+1-2*0))/(0^2+1)^2=1