Решите систему уравнений алгебра, 7 класс

$6y - 5x = 1 \\ \frac{x - 1}{3} + \frac{y + 1}{2} = 10 \\ \\ 6y - 5x = 1 \\ \frac{2(x - 1)}{6} + \frac{3(y + 1)}{6} = \frac{60}{6} \\ \\ 6y - 5x = 1 \\ 2x - 2 + 3y + 3 = 60 \\ \\ 6y - 5x = 1 \\ 3y + 2x = 59 \\ \\ 6y - 5x = 1 \\ 6y + 4x = 118 \\ \\ 9x = 117 \\ y = \frac{1 + 5x}{6} \\ \\ x = 13 \\ y = \frac{1 + 65}{6} = \frac{66}{6} = 11$
Ответ: (13; 11)