ПОМОГИТЕ пожалуйста с УРАВНЕНИЕМ !!!

${( \frac{ {x}^{2} - x + 2}{2} )}^{2} - 2 \times ( \frac{ {x}^{2} - x + 2}{2} ) \times ( \frac{ {x}^{2} - x + 18}{3} ) + {( \frac{ {x}^{2} - x + 18 }{3} )}^{2} = 0 \\ {( \frac{ {x}^{2} - x + 2 }{2} - \frac{ {x}^{2} - x + 18 }{3}) }^{2} = 0 \\ \frac{ {x}^{2} - x + 2 }{2} - \frac{ {x}^{2} - x + 18}{3} = 0 \\ 3( {x}^{2} - x + 2) - 2( { x }^{2} - x + 18) = 0 \\ 3 {x}^{2} - 3x + 6 - 2 {x}^{2} + 2x - 36 = 0 \\ {x}^{2} - x - 30 = 0 \\ d = {b}^{2} - 4ac = 1 - 4 \times 1 \times ( - 30) = 1 + 120 = 121 \\ x1 = \frac{1 + 11}{2} = \frac{12}{2} = 6 \\ x2 = \frac{1 - 11}{2} = \frac{ - 10}{2} = - 5$
Ответ: -5; 6.