Решите плиз алгебру

㏒6(㏒7( $\sqrt[12]{7^2}$ )) + 9㏒8( $\sqrt[3]{2^4}$ )=

㏒6(㏒7( $\sqrt[6]{7}$ )) + 9㏒2^3( $\sqrt[3]{2^4}$ )=

㏒6(1/6*㏒7(7)) + 9(4/3*3)㏒2(2)=㏒6(1/6*1) + 4*1=-1 + 4= 3

2) $18^{\frac{1}{1+log9(2)}}=18^{\frac{1}{log9(9)+log9(2)}}=18^{\frac{1}{log9(9*2)}}=18^{\frac{1}{log9(18)}}=18^{log18(9)}=9$

3) log√3(5)*log25(6)*log6(27)=

log $3^{1/2}$ (5)*log $5^2$ (6)*log6( $3^3$ )=

2*2*3log3(5)*log5(6)*log6(3)=12log3(5)*log5(6)*log6(3)=

12log3(5)*log5(6)*(log5(3)/log5(6))=12log3(5)*log5(3)=

12log3(5)*(1/log3(5))=12