Даю 50 баллов срочно

Question

Даю 50 баллов срочно

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Answer 1

a) (х - у)/(ху) - (х - z)/(xz) = [z · (x - y) - y · (x - z)] / (xyz) = (xz - yz - xy + yz)/(xyz) =

= (xz - xy)/(xyz) = [x(z - y)]/(xyz) = (z - y)/(yz) = 1/y  - 1/z

б) (a - 2b)/(3b) - (b - 2a)/(3a) = [a · (a - 2b) - b · (b - 2a)]/(3ab) =

=  (a² - 2ab - b² + 2ab)/(3ab) = (a² - b²)/(3ab) = a/(3b) - b/(3a)

в)  (6a - 4b)/5 - (b + 7a)/3 - 2/1 = [3 ·  (6a - 4b) - 5 · (b + 7a) - 15 · 2]/15 =

= (18a - 12b - 5b - 35a - 30)/15 = (-17a - 17b - 30)/15 = - 17(a + b)/15 - 2

Answer 2

a) (х - у)/(ху) - (х - z)/(xz) = [z · (x - y) - y · (x - z)] / (xyz) = (xz - yz - xy + yz)/(xyz) =

= (xz - xy)/(xyz) = [x(z - y)]/(xyz) = (z - y)/(yz) = 1/y  - 1/z;

б) (a - 2b)/(3b) - (b - 2a)/(3a) = [a · (a - 2b) - b · (b - 2a)]/(3ab) =

=  (a² - 2ab - b² + 2ab)/(3ab) = (a² - b²)/(3ab) = a/(3b) - b/(3a);

в)  (6a - 4b)/5 - (b + 7a)/3 - 2/1 = [3 ·  (6a - 4b) - 5 · (b + 7a) - 15 · 2]/15 =

= (18a - 12b - 5b - 35a - 30)/15 = (-17a - 17b - 30)/15 = - 17(a + b)/15 - 2.