x = \frac{\pi}{6} + \pi k, k \in \mathbb{Z}" alt="tg(x) = \frac{1}{\sqrt{6} - \sqrt{3}} - \frac{\sqrt{6}}{3} = \frac{3(\sqrt{2} - 1)}{3\sqrt{3}(\sqrt{2} - 1)} = \frac{1}{\sqrt{3}} \\
x = \frac{\pi}{6} + \pi k, k \in \mathbb{Z}" align="absmiddle" class="latex-formula">
На промежутке есть 2 решения: 
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