Розв'яжить ривняння 1. 4^(x) = 9 2. 10^(3x+1)=8 3. 6^(x-5)=24

x=log_4(9)=>x=log_{2^2}(3^2)=>x=log_2(3)" alt="4^x=9=>x=log_4(9)=>x=log_{2^2}(3^2)=>x=log_2(3)" align="absmiddle" class="latex-formula">
3x+1=log_{10}(8)=>3x=3log_{10}(2)-1=>x=log_{10}(2)-1\\x=log_{10}(2)-\frac{1}{3}" alt="10^{3x+1}=8=>3x+1=log_{10}(8)=>3x=3log_{10}(2)-1=>x=log_{10}(2)-1\\x=log_{10}(2)-\frac{1}{3}" align="absmiddle" class="latex-formula">
x-5=log_6(24)=>x=log_6(24)+4\\24=6*4=>x=log_6(6)+log_6(4)+5=>x=6+2log_6(2)" alt="6^{x-5}=24=>x-5=log_6(24)=>x=log_6(24)+4\\24=6*4=>x=log_6(6)+log_6(4)+5=>x=6+2log_6(2)" align="absmiddle" class="latex-formula">