Решите неравенство (1/3)^2-4x<1/27
\frac{1}{54}\\x\in(\frac{1}{54};+\infty)" alt="(\frac{1}{3})^{2}-4x<\frac{1}{27}\\\frac{1}{9}-4x<\frac{1}{27}\\-4x<\frac{1}{27}-\frac{1}{9}\\-4x<-\frac{2}{27}\\x>\frac{1}{54}\\x\in(\frac{1}{54};+\infty)" align="absmiddle" class="latex-formula">