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Решите задачу:

$1)3\frac{2}{5}+1\frac{5}{7}=\frac{17}{5}+\frac{12}{7}=\frac{17*7+12*5}{35}=\frac{179}{35}\\\\2)\frac{179}{35}*11\frac{2}{3}=\frac{179}{35}*\frac{35}{3}=\frac{179*35}{35*3}=\frac{179}{3}\\\\3)1\frac{2}{9}-1\frac{1}{18}=\frac{11}{9}-\frac{19}{18}=\frac{11*2-19*1}{18}= \frac{3}{18}= \frac{1}{6}\\\\4)\frac{179}{3}:\frac{1}{6}=\frac{179}{3}*\frac{6}{1}=\frac{179*6}{3*1}=179*2=358\\\\5)10\frac{3}{4}-1\frac{5}{6}=\frac{43}{4}-\frac{11}{6}=\frac{43*3-11*2}{12}=\frac{107}{12}$

$6)\frac{107}{12}*6= \frac{107*6}{12}=\frac{107}{2}\\\\7)5\frac{3}{20}-4\frac{1}{4}=\frac{103}{20}-\frac{17}{4}=\frac{103*1-17*5}{20}=\frac{18}{20}=\frac{9}{10}\\\\8)\frac{9}{10}*1\frac{1}{9}=\frac{9}{10}*\frac{10}{9}=\frac{9*10}{10*9}=1\\\\9)\frac{107}{2}:1=\frac{107}{2}\\\\10)358-\frac{107}{2}=\frac{358*2-107}{2}=\frac{609}{2}\\\\11)\frac{609}{2}:42\frac{1}{2}=\frac{609}{2}:\frac{85}{2}=\frac{609*2}{2*85}=\frac{609}{85}=7\frac{14}{85}$