(√3−2)^(2)−(√3−5)(√3−1)=?

Question

(√3−2)^(2)−(√3−5)(√3−1)=?

Answer 1

(√3−2)²−(√3−5)(√3−1) =

= ((√3)² - 2*√3*2 + 2²) - ((√3)² - √3 - 5√3 +5) =

= 3 - 4√3 + 4 - 3 + √3 + 5√3 -5 =

= 2√3 - 1