Ответ:
Пошаговое объяснение:
y'=7\frac{4}{7} x^{6\frac{4}{7} }\\y=2x^{\frac{1}{2} +\frac{2}{5} }=2x^{\frac{9}{10} }=>y'=1\frac{4}{5} x^{-\frac{1}{10}}\\ y=2,4x^{\frac{1}{2} +\frac{2}{3} }=2,4x^{1\frac{1}{6} }=>y'=2,8x^{\frac{1}{6} }" alt="y' = 9*\frac{4}{9} x^{\frac{4}{9} -1} +5*\frac{3}{5} x^{\frac{3}{5} -1}= 4x^{-\frac{5}{9} }+3x^{-\frac{2}{5} }\\y'=2x^{-\frac{7}{9} }+x^{-\frac{5}{6}}+4x^{-\frac{3}{5} }+2x^{-\frac{2}{3}}+2\\ y=x^{7+\frac{4}{7} }=>y'=7\frac{4}{7} x^{6\frac{4}{7} }\\y=2x^{\frac{1}{2} +\frac{2}{5} }=2x^{\frac{9}{10} }=>y'=1\frac{4}{5} x^{-\frac{1}{10}}\\ y=2,4x^{\frac{1}{2} +\frac{2}{3} }=2,4x^{1\frac{1}{6} }=>y'=2,8x^{\frac{1}{6} }" align="absmiddle" class="latex-formula">
(xⁿ)' = nxⁿ⁻¹